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    Upvotes150Top Answeranswered Dec 5, 2009 at 10:46
    $file = '../image.jpg';
    $type = 'image/jpeg';
    header('Content-Type:'.$type);
    header('Content-Length: ' . filesize($file));
    readfile($file);
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  1. Output an Image in PHP - Stack Overflow

    WEBApr 13, 2015 · $file = '../image.jpg'; $type = 'image/jpeg'; header('Content-Type:'.$type); header('Content-Length: ' . filesize($file)); $img = file_get_contents($file); echo $img; This is works for me! I have test it on …

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    • PHP: readfile - Manual

      WEBFilesystem Functions. Change language: readfile. (PHP 4, PHP 5, PHP 7, PHP 8) readfile — Outputs a file. Description ¶. readfile ( string $filename, bool $use_include_path = false, ? resource $context = null ): int | false. Reads a file and writes it to the output buffer. Parameters ¶. filename. …

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      In PHP, you can output an image using the built-in function header() to set the content type to an image format and the readfile() function to read the image file and output its contents. For example, to output a JPEG image, you can use the following code: readfile ( 'path/to/image.jpg' );
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