GRAMMAR FOR THE LANGUAGE:{a^n b^n c^n/n>=1}. S->abc|A. A->aABc|abc. cB->Bc. bB->bb. FOR EXAMPLE:INPUT STRING aaabbbccc when n=3. S->A. ->aAB...

This gives the language: $L = \{a^n b^n c^n c^m | n,m>=0\}\,. $. S → a b c C | N | ε. N → a N B c C | a b c C. c B → W B. W B → W X. W X → B X...

There is a solution which is context-sensitive. $$G = (N,T,P,S)$$ $$N=\{S,A,B,C\}$$ $$T=\{a,b,c\}$$ $$S=\mbox{start symbol}$$ Production Rules(P):...