How to use the __attribute__ ( (visibility ("default")))?
ウェブ2018年10月9日 · Modified to make all symbols hidden by adding -fvisibility=hidden. someproj.so : someproj.cpp. g++ --std=c++11 -O3 -fvisibility=hidden -fPIC -shared someproj.cpp -o someproj.so. Is it possible to customized which functions are exposed by modifying the compilation command above? Currently using 4.7.2 version of gcc. c++. …
What does GCC visibility hidden do in those cases?
ウェブ2014年12月21日 · It may be better to mark the method as "private" (if possible), which will give your users a better error-message experience. Since m_links and m_offsets are already private, there is no way for outside code to get to them. More importantly, they don't have linker symbols, so there is nothing to hide.
linux - C++ -fvisibility=hidden -fvisibility-inlines-hidden - Stack ...
ウェブ2 Answers. Sorted by: 55. -fvisibility=hidden makes all your symbols hidden by default. What you then have to do, is choose which functions you want to be visible to users linking against your library and make them visible by marking them with a visible attribute. E.g. void __attribute__((visibility("default"))) Exported() { // ... }
gcc - Hiding symbol names in library - Stack Overflow
ウェブ2014年3月7日 · 4 Answers. Sorted by: 50. The visibility("hidden") attribute does not suppress a symbol from an object file and cannot prevent a symbol being extracted by nm. It just instructs the dynamic linker that the symbol cannot be called from outside a shared library that contains it. Consider a source file file.c containing your example functions:
How to apply -fvisibility option to symbols in static libraries?
ウェブ2018年8月27日 · 3 Answers. Sorted by: 86. Simply pass -Wl,--exclude-libs,ALL to gcc. This will tell the linker to transform all the symbols in the static libraries to hidden. --exclude-libs also accepts a list of archives (i.e. static library names) for finer granularity on which libraries to hide symbols from.
c++ - Symbol visibility and namespace - Stack Overflow
ウェブ2013年3月22日 · It seems that the preferred way is to use -fvisibility=hidden, and export used symbols one-by-one according to Visibility gcc wiki page ( http://gcc.gnu.org/wiki/Visibility ). My problem is that many libraries does not handle this well, they forget to explicitly export symbols, which is a serious problem.
How -fvisibility-inlines-hidden differs from -fvisibility=hidden in gcc
ウェブ2019年12月24日 · 1 Answer. Sorted by: 4. According to http://gcc.gnu.org/wiki/Visibility. ... command line switch: -fvisibility-inlines-hidden. This causes all inlined class member functions to have hidden visibility, causing significant export symbol table size & binary size reductions though not as much as using -fvisibility=hidden.
How to hide a global variable, which is visible across multiple ...
ウェブ4 Answers. Sorted by: 10. You want the visibility attribute extension of GCC. Practically, something like: #define MODULE_VISIBILITY __attribute__ ((visibility ("hidden"))) #define PUBLIC_VISIBILITY __attribute__ ((visibility ("default")))
[[deprecated]] + __attribute__ ((visibility ("default"))) in GCC 6.2
ウェブ2016年11月30日 · The c++11 style attribute [[gnu::visibility("default")]] works for classes, but not for functions (the code compiles, but produces a -Wattributes warning and the symbol is left out when built with -fvisibility=hidden ). Is this a bug in the compiler (I used GCC 6.2 for these tests) or something specified by c++ standard?
What is the CMake equivalent to "gcc -fvisibility=hidden ...
ウェブ2013年6月13日 · 2 Answers. Sorted by: 117. Instead of setting compiler flags directly, you should be using a current CMake version and the <LANG>_VISIBILITY_PRESET properties instead. This way you can avoid compiler specifics in your CMakeLists and improve cross platform applicability (avoiding errors such as supporting GCC and not …
コンテンツに移動