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SOLVED: The annulus shown in Figure 1 carries a uniform
In cylindrical coordinates (r, θ, z), the potential V only depends on z, so we have: E = -∂V/∂z ȕz where ȕz is the unit vector in the z-direction. Taking the derivative of V(z) with respect to z, we get: ∂V/∂z = 4πkρz/(z^2 + a^2)^(3/2) where ρz is the surface charge density on the annulus.Explore further
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