First of all, your form should be something like so: <form action="page_you_want_to_display.php" method="POST"> <label for="type">Job Type:</l...

may be problem in your php. Is there some logic? $job_type=null; if($job_type=='fulltime'){ ... if($job_type=='parttime'){ ... } }...

I don't believe that the conditions will work the way you implemented it, try doing it like this: <?php echo "<div class='job_type_div'>"; if($job_...

While you fetching your array from Data Base you need to use MYSQL_BOTH, to fetch columns by Name. mysql_fetch_array($res, MYSQL_BOTH) So you s...

form.php if you initially set one 'selected' in your form, dont need to check if its set, simple set db like so: ... mysql_query("UPDATE X SET (job...